Table of contents
- 1. Intro to Stats and Collecting Data24m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically1h 45m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables1h 16m
- 6. Normal Distribution and Continuous Random Variables58m
- 7. Sampling Distributions & Confidence Intervals: Mean1h 3m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 5m
- 9. Hypothesis Testing for One Sample1h 1m
- 10. Hypothesis Testing for Two Samples2h 8m
- 11. Correlation48m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 20m
- 14. ANOVA1h 0m
6. Normal Distribution and Continuous Random Variables
Standard Normal Distribution
Problem 6.q.7
Textbook Question
Seat Designs. In Exercises 7–9, assume that when seated, adult males have back-to-knee lengths that are normally distributed with a mean of 23.5 in. and a standard deviation of 1.1 in. (based on anthropometric survey data from Gordon, Churchill, et al.). These data are used often in the design of different seats, including aircraft seats, train seats, theater seats, and classroom seats.
Find the probability that a male has a back-to-knee length greater than 25.0 in.

1
Step 1: Identify the key parameters of the normal distribution. The problem states that the back-to-knee lengths are normally distributed with a mean (μ) of 23.5 inches and a standard deviation (σ) of 1.1 inches.
Step 2: Define the event of interest. We are tasked with finding the probability that a male has a back-to-knee length greater than 25.0 inches. This corresponds to P(X > 25.0), where X represents the back-to-knee length.
Step 3: Standardize the value of 25.0 inches using the z-score formula: z = (X - μ) / σ. Substitute the values: X = 25.0, μ = 23.5, and σ = 1.1. This will give the z-score corresponding to 25.0 inches.
Step 4: Use the z-score obtained in Step 3 to find the cumulative probability from a standard normal distribution table or using statistical software. The cumulative probability corresponds to P(Z ≤ z), where Z is the standard normal variable.
Step 5: Since we are interested in P(X > 25.0), calculate the complement of the cumulative probability found in Step 4. This is given by P(X > 25.0) = 1 - P(Z ≤ z).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Normal Distribution
Normal distribution is a probability distribution that is symmetric about the mean, depicting that data near the mean are more frequent in occurrence than data far from the mean. It is characterized by its bell-shaped curve, defined by its mean and standard deviation. In this context, the back-to-knee lengths of adult males follow a normal distribution, which allows for the calculation of probabilities related to specific length values.
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Mean and Standard Deviation
The mean is the average of a set of values, while the standard deviation measures the amount of variation or dispersion in a set of values. In this scenario, the mean back-to-knee length is 23.5 inches, and the standard deviation is 1.1 inches. These statistics are crucial for understanding the distribution of lengths and for calculating probabilities of lengths exceeding a certain value.
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Calculating Standard Deviation
Z-Score
A Z-score indicates how many standard deviations an element is from the mean. It is calculated by subtracting the mean from the value of interest and then dividing by the standard deviation. In this case, to find the probability that a male has a back-to-knee length greater than 25.0 inches, one would first calculate the Z-score for 25.0 inches, which can then be used to find the corresponding probability from the standard normal distribution table.
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